1.

Derive a relation between DeltaG^(@) and equilibrium constant K, for the reaction- aA + bB hArr cC + dD

Answer»

Solution : Consider FOLLOWING reversible reaction,
`aA + bB hArr CC + DD`
The reaction quotient Q is,
`Q = ([C]^(c) xx[D]^(d))/([A]_(e)^(a) xx [B]^(b))`
The free energy change dG for the reaction is
`DELTAG = DeltaG^(@)RT` in Q
Where `DeltaG^(@)` is the standard free energy change.
At equilibrium
`Q = ([C]_(e)^(c) xx[D]_(e)^(d))/([A]_(e)^(a) xx [B]_(e)^(b)) = k`
`therefore DeltaG = DeltaG^(@) +RT` in K
`because` at equilibrium `DeltaG` = 0
`therefore 0 = DeltaG^(@) +RT` in K
`therefore DeltaG^(@) = - RT` in K `therefore DeltaG^(@) = - 2 .303RTlog_(10) k`.


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