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Derive a relationship between dissociation constant K_(a) and molar conductivity wedge_(m). |
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Answer» Solution :According to Ostwald dilution Law, `""K_(a)=(alpha^(2)C)/((1-alpha))"...(1)"` SUBSTITUTE a VALUE in the above expression (1) `""K_(a)=(wedge_(m)^(2)C)/(wedge_(m)^(2)(1-wedge_(m)/(wedge_(m)^(@))))` `""K_(a)=(wedge_(m)^(2)C)/(wedge_(m)^(2)(wedge_(m)^(@)-wedge_(m))/wedge_(m)^(@))` `RARR K_(a)=(wedge_(m)^(2)C)/(wedge_(m)^(@)(wedge_(m)^(@)-wedge_(m)))`. |
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