1.

Derive an expression for centripetal acceleration in terms of angular speed.

Answer»

Solution :For an object revolving with linear speed V at a distance r from the center of rotation, the CENTRIPETAL ACCELERATION is given by the equation `a_(c)=v^(2)//r`. Using the FUNDAMENTAL equation v=r`omega`, we find that ,BRGT `d_(c)=(v^(2))/(r)=((romega)^(2))/(r)=omega^(2)r`.


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