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Derive an expression for the electric potential at any point along the axial line of an electric dipole. |
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Answer» <P> Solution :Consider a point P situated at a distance R from mid-point of an electric dipole along its axial line.Electric potential at P DUE to +ve CHARGE at B,` V_B = 1/(4pi epsi_0) . q/((r-a))`  and electric potential at P due to - ve charge at A, `V_A = 1/(4pi epsi_0). ((-q))/((r+a))` `:.` Net electric potential at point P, `V = V_B + V_A = 1/(4pi epsi_0) . q/((r-a)) - 1/(4pi epsi_0) .q/((r + a))` `=q/(4 pi epsi_0)[1/((r-a)) - 1/((r + a))] = q/(4pi epsi_0) . (2a)/((r^2 -a^2)) = p/(4pi epsi_0(r^2 - a^2))` If `r gt gt a`, then we have `V = p/(4pi epsi_0r^2)`. |
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