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Derive an expression for the hydrolysis constant and degree of hydrolysis of salty ofstrong acid and weak base. |
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Answer» Solution :Hydrolysis of salt of strong acid and weak base : Let us consider the reactions between a strong acid, HCI, and a weak base, `NH_4OH`, to produce a salt, `NH_4CI`, and water `HCI_((aq))+NH_4OH_((aq)) hArr NH_4 CI_((aq))+H_2 O (I)` `NH_4 CI_((aq)) to NH_(4)^(+)+CI_((aq))^(-)` `NH_4^+`is a strong conjugate acid of the weak base `NH_4OH` and it has a tendency to react with `OH^-` from water to produce unionised `NH_4OH` shown below. `NH_(4(aq))^(+)+H_2O(I) hArr NH_4OH_((aq))+H_((aq)^+` There is no such tendency shown by `CI^-` and THEREFORE `[H^+] gt [OH^-]`, the solution is acidic and the PH is less than 7. As discussed in the salt hydrolysis of strong base and weak acid. In this case also, we can establish a relationship between the `K_(h) and K_(b)` as `k_(h).K_(b)=K_(w)` Let us calculate the `K_(h)` value in terms of degree of hydrolysis (h) and the concentration of salt `K_(h)=h^2 C and [H^+]=sqrt(K_(h).C)` `[H^+]=sqrt((K_w)/(K_b).C)` `pH=-log[H^+]` `=-log((K_w.C)/(K_b))^(1/2)` `=-(1)/(2)logK_w-(1)/(2)logC+(1)/(2)logK_(b)` `pH=7-(1)/(2)pK_(b)-(1)/(2)logC.` |
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