Derive an expression for the hydrolysis constant for the hydrolysis of salt of weak acid and weak base.

Derive an expression for the hydrolysis constant for the hydrolysis of

1.	Derive an expression for the hydrolysis constant for the hydrolysis of salt of weak acid and weak base.
Answer» Solution :Let us consider the hydrolysis of AMMONIUM acetate. `CH_3COONH_(4(aq)) to CH_3 COO_((aq))^-+NH_(4(aq))^-+NH_(4(aq))^+` In this case, both the cation `(NH_4^+)` and anion `(CH_3 COO^3-)` have the tendency to react with WATER `CH_3 COO^-hArrCH_3 COOH+OH^-` `NH_4^(+)+H_2O hArr NH_4 OH+H^+` The natural of the solution DEPENDS on the strength of acid (or) base i.e., if `K_a gt K_b`,then the solution is acidic and `pH lt 7`, If `K_a lt K_b`, then the solution is basic and `pH gt 7`, if`K_a=K_b`, then the solution is neutral The relation between the dissociation constant `(K_a, K_b)` and the hydrolysis constant is given be the following expression. `K_a.K_b.K_h.=K_w` pH of the solution pH of the solution can be calculated using the following expression, `pH=7+(1)/(2)pK_(1)-(1)/(2)pK_(b)`