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Derive an expression of affective resistance of four resistors connected in parallel. |
Answer» Solution : A CURRENT I enterining the combination gets dvided into `I _(1), I _(2), I _(3) and I_(4)` through `R_(1), R_(2), R_(3) and R_(4)` respectively. such that `I=I_(1) + I_(2) + I_(3) +I_(4)` By Ohm.s law `I_(1)= (V)/(R_(1)), I _(2) = (V)/(R_(2)), I _(3) = (V)/(R_(3)) , I _(4) = (V)/(R_(4)) and I = (v)/(R_(P))` where `R_(P)` is the equivalent of effective RESISTANCE of the paralel CONBINATION. `therefore (V)/( R _(P)) = (V)/( R _(2)) + (V)/( R _(2)) + (V)/( R _(3)) + (V)/( R _(4))` `(1)/( R _(P)) =(1)/( R _(1)) + (1)/( R _(2)) + (1)/( R _(3)) + ( 1 )/( R _(4))` |
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