1.

Derive an integrated rate equation for rate constant of a zero order reaction.

Answer»

Solution :(a) `{:("LET us consider the following reaction which is of zero order."),(""R to P),("The rate is GIVEN by "),(""(-d[R])/(dt) = K[R]^(0)),(""(-d[R])/(dt) = k),(""-d[R] = kdt),(""d[r} = -kdt),("On integration"),(""int d[R] = -k int dt),(""[R] = -kt + I):}}......(i)`
`{:("Where , I is integration constant"),("When t = 0"),([R] = [R_0]"where " R_0 "is initial concentration of the reactant"),(""[R_0] = - k xx 0 + I),(""[R]_0 = I):}}`
`:. ` EQUATION (i) becomes
`{:([R] = -kt + [R]_(0)),(kt = [R]_(0) - [R]),(k = ([R]_(0) - [R])/(t)):}}.......(ii)`
(b) (i) `k = Ae (-E a)/(RT) ` OR Any other suitable form of equation.
(ii) `t_(1//2) = ([R]_(0)]/(2k)`.


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