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Derive an integrated rate equation for the rate constant of a zero order reaction. |
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Answer» Solution :(a) Consider a REACTION which is of zero order, `Rrarr P` `Rate = -d[R]/dt = K[R]^(0) = -d[R]/dt = K` `d[R] = -kdt` integrating both sides we get, `int d[R] = int-kdt` [R] = -kt + 1 where, I is the constant of integration. When t = 0, [R] = [R]0, where [R]0 is initial concentration of the REACTANT. Substituting in equation (i) we get, `[R]0 = -k XX 0 + 1` [R]0 = 1: Substituting the VALUE of I in equation (i), we get, `[R] = -kt + [R]^(0)` `kt = [R]^(0) - [R]` `k = ([R]^(0) - [R])/t` (b)
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