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Derive integrated rate equation for rate constant for a first order reaction. |
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Answer» SOLUTION :`R to P` Rate`=-(d[R])/(dt)=k[R] or (d[R])/([R])=-kdt` Integrating this equation In [R]`=-kt+I ""…(i)` where I is constant of integration. When `t=0, R=[R]_(0)`, where `[R]_(0)` is initial concentration. The equation (i) can be written as `"In [R]_(0)= -k xx 0+I` or `"In [R]_(0)=I` Substituting the value of I in equation (i) `"In [R]"= -kt +"In [R]"_(0) or -kt = "In [R]" -"In [R]"_(0)` or `k=(1)/(t)"In"([R]_(0))/([R]) or k-(2.303)/(t)"log"([R]_(0))/([R])` |
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