Saved Bookmarks
| 1. |
Derive relation between kappa_(a) and Lamda_(m)^(@) for solution of weak electrolyte. |
|
Answer» SOLUTION :* At CONSTANT temperature, solution of weak electrolyte solution, If `alpha`=DEGREE of dissociation of solution c=concentration of solution in MOLARITY `Lamda_(m)`=MOLAR conductivity of solution `Lamda_(m)^(@)`=limiting molar conductivity of solution `therefore alpha=(Lamda_(m))/(Lamda_(m)^(@))=("Molar resistivity of solution")/("Limiting molar resistivity of solution")` * For weak electrolyte like acetic acid, `therefore kappa_(a)=(calpha^(2))/((1-alpha))=(cLamda_(m)^(2))/((Lamda_(m)^(@))^(2)(1-(Lamda_(m))/(Lamda_(m)^(@))))` `kappa_(a)=(cLamda_(m)^(2))/(Lamda_(m)^(@)(Lamda_(m)^(@)-Lamda_(m)))`. |
|