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Derive the expression for equivalent spring constant of `(i)` parallel combination of `n-`springs `(ii)` series combination of `n-`springs |
Answer» Correct Answer - (a) (i) Let extension in each spring is `x` then `F_(1) = K_(1)x_(1)` `F_(2) = K_(2)x_(1), F_(3) = K_(3)x = …… = K_(n)x` `F_(1) + F_(2) + F_(3) + ….. + F_(n) = F` `rArr K_(1)x + K_(2)x + K_(3)x + ...... + K_(n)x = K_(eq)x` `rArr K_(eq) = K_(1) + K_(2) + K_(3) + .... + K_(n)` (ii) Let `F` be the force in each spring and `x_(1), x_(2), x_(3)......x_(n)` are the extensions in different springs then `F = K_(1)x_(1) = K_(2)x_(2) = K_(3)x_(3) = ....... = K_(n)x_(n)` `x_(1) + x_(2) + x_(3) .... + x_(n) = x` `rArr (F)/(K_(1)) + (F)/(K_(1)) + (F)/(K_(3)) + ....... + (F)/(K_(n)) = (F)/(K_(eq))` `rArr (F)/(K_(eq)) = (F)/(K_(1)) + (F)/(K_(2)) + (F)/(K_(3)) +.........+ (F)/(K_(n))` |
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