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Derive the expression for the electricpotential at any point along the axial line of an electric dipole. |
Answer» Solution :Deivation of expression of electric FIELD on the equatoral line of the DIPOLE. Both are equal and their DIRECTION are as shwon in the figure. Hence net electric field `E_(+q)=q/(4piepsilon_(0)(r^(2)+a^(2)))` `E_(-q)=q/(4piepsilon_(0)(r^(2)+a^(2)))` Let the point P be the at a distance r form the mid point of the dipole. `VEC(E)=[-(E_(+q)+E_(-q)cosq]hatp` `=-(2qa)/(4piepsilon_(0)(r^(2)+a^(2))^(3//2))hatp` |
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