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Derive the integrated rate equation for rate constant of a zero reaction. |
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Answer» Solution :Consider a zero order reaction. `R to P` `(-d[R])/(dt) = K[R]^(1)` Where k is velovity constant of a first order reaction. `(-d[R])/([R]) = -k.dt` Inegrating the EQUATION `int(d[R])/([R]) = -intk.dt` In `[R] = -kt +1 ""...(1)` I si constant of integration WHen t = 0 [R] ` = [R]_(0)` Where `[R]_(0)` is initial concentration of the reaction In `[R]_(0) = - k xx 0 +1` `I = "In" [R]_(0)` Substituing I value in equation (1) In `[R] = -kt + "In" [R]_(0)` kt = In `[R]_(0) = "In" [R]` `k = (2.303)/(t) LOG""([R]_(0))/([R])` |
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