Saved Bookmarks
| 1. |
Derive the integrated rate law for afirst order reaction ? |
|
Answer» Solution :A reaction rate depends on the reactant concentration raise to the power is called a first ORDER reaction. First order reaction. `A rarr` product Rate law can be expressedas Rate `=k[A]^1` Where, k is the first order rate constant `(-d[A])/(dt)=k[A]^1` `=(-d[A])/([A])=k dt""...(1)` Integrate the above equation (1) between the limits of time t = - time equal to t , while the concentration varies from initial concentration `[A_0]" to" [A]` at the later times. `int_(A_0)^(A) (-d[A])/([A])=kint_0^t dt` `-LN[A]_A_0^A=k(t)_0^t` `-ln[A]-[In[A_0])=k(t=0)` `ln[A]+In [A_0]=kt ` `ln(([A_0])/([A]))=kt""...(2)` This equation (2) is in natural logarithm . to convert it into usual logarithm the with base 10 , we have to MULTIPLY the term by 2.303 `2.303log(([A_0])/([A]))=kt` `k=2.303/tlog(([A_0])/([A]))"".....(3)` |
|