1.

Derive the order of reaction for decomposition of H_(2)O_(2) from the following data. {:("Time (in minutes)",10,15,20,25,oo),("Volume of" O_(2) "given",6.30,8.95,11.40,13.5,35.75):} by H_(2)O_(2)

Answer»

Solution :Volume of `O_(2)` at any given time `PROP` Moles of `H_(2)O_(2)` decomposed
`:. a prop 35.75`
At `t=10, x prop 6.30`
`K=2.303/10 "LOG" 35.75/(35.75-6.30)`
`=1.94xx10^(-2)`
At `t=15, x prop 8.95`
`K=2.303/15 "log" 35.75/(35.75-8.95)`
`=1.94xx10^(-2)`
At `t=20, x prop 11.40`
`K=2.303/20 "log" 35.75/(35.75-11.40)`
`=1.94xx10^(-2)`
At `t=25, x prop 13.50`
`K=2.303/25 "log" 35.75/(35.75-13.50)`
`=1.94xx10^(-2)`
SINCE `K` values are constant using first order equation and thus, reaction OBEYS first order kinetics
`K=1.92xx10^(-2) min^(-1)`


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