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Derive the relation vec(j)=sigmavec(E) with terms which has usual meaning. |
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Answer» SOLUTION :We know from the Ohm.s law, I = KV where, I- electric CURRENT, K - CONDUCTANCE and V - potential difference Dividing I= KVby `.^^.` on both sides we get, `I/A=K/A V` by definition electric current density `j=I/A` Hence `j=(K/A)V` But electric field , `E=V/l` or V=EL hence `j=(K/A)(El)` where `SIGMA=(Kl)/A` is known as theelectricalconductivity . Hence `j=sigmaE`. In a vectorform , the relationis written as `vecj=sigmavecE` . |
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