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Derive the value of pH of salt solution in terms of K_a and concentration of electrolyte. |
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Answer» SOLUTION :`pH+poH=14` `pH=14-pOH` `=14-[-log_10[OH^-]` `=14+log[OH^-]` `THEREFORE pH=14+log[K_hC]^(1//2) ` `pH=14+log[(K_wC)/K_a]^(1/2)` `pH=14+(1/2logK_w+1/2logC-1/2logK_a)` `pH=14-7+1/2logC-1/2log K_a` `pH=14-7+1/2logc+1/2pK_a because-logK_a=pK_a` `therefore pH=7+1/2 pK_a+1/2 log C` |
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