1.

Derive the value of solubility produce from molar solubility?

Answer»

Solution :(i) Solubility can be calculated from MOLAR stability.
i.e, the maximum number of MOLES of the solute that can be dissolved in one litre of the solution.
(ii) For a solute `X_m Y_n`
`X_mY_n(s) LEFTRIGHTARROW mX^(n+)(aq)+nY^(m-) (aq)`
From the above stoichiometricall BALANCED equation, it is clear that 1 mole of `X_m Y_n (s)` dissociated to furnish m moles of x and n moles of Y. If is the molar solubility of `X_m Y_n` then
`[X^(n+)]=ms and [Y^(m-)]=ns`
`therefore K_(sp)=[X^(n+)]^m [Y^(m-)]^n`
`K_(sp)=(ms)^m (ns)^n`
`K_(sp)=(m)^m (n)^n (s)^(m+n)`


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