1.

Derive theexpressionforintergrated ratelaw for zeroorderreaction A to Products.

Answer»

Solution :Considera zero order , `A to ` Products
The rateof thereactionis ,
Rate ` =(-d[A])/(DT)`
By ratelaw,
Rate` = k xx [A]^(0) = k`
`therefore- d[A] = k xx dt`
If `[A]_(0)`is theinitial CONCENTRATIONOF the reaction A at t= 0AND `[A]_(t)` isthe concentration of A present after time t, then by integratingabove equation,
`UNDERSET([A]_(0))overset([A]_(t))int - d[A] = underset(t = 0)overset( t= t)intkdt`
`underset([A]_(0))overset([A]_(t))int - d[A] = underset( 0)overset( t)intkdt`
`-[A]_([A]_(0))^([A]_(t)) = k [t]_(0)^(t)`
` - ([A]_(t) - [A]_(0)) = kt`
`therefore [A]_(0) - [A] _(t) = kt`
` therefore k= ([A]_(0) - [A]_(t))/(t)`
This is the integrated rate law EXPRESSION for rate constant for zeroorder reaction.


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