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Derived force on moving charge in uniform magnetic field with velocity vecv_. |
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Answer» SOLUTION :1. CURRENT induced from moving charge q with velocity `VECV` form uniform sectional wire, `I=nAvq` `thereforeIdvecl=nAvqdvecl` 2. Magnetic force acting on `Idvecl` SMALL current carrying element in uniform magnetic FIELD `vecB` is given as, `dvecF=IdveclxxvecB` `=nAvecvqdlxxvecB` `thereforedvecF=nAqdl(vecvxxvecB)""...(1)` but nAdl = number density of charge in dl element. 3. Magnetic force on q electric charge, `vecF_(m)=(dvecF)/(nAdl)=(nAdlq(vecvxxvecB))/(nAdl)` `thereforevecF_(m)=q(vecvxxvecB)` |
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