Saved Bookmarks
| 1. |
Describe the action of the following on chlorobenzene :Methyl chloride in the presence of anhydrous AlCl_(3) |
|
Answer» Solution :Methyl chloride in the presence of ANHYDROUS `AlCl_(3)` : When chlorobenzence is TREATED with methyl chloride in the presence of anhydrous `AlCl_(3),` a mixture of 1-chloro-4-methyl benzence (major product) and 1-chloro-2-methyl benzence is formed. Since, the alkyl group is introduced in the benzene RING, the reaction is termed as Friedel Crafts alkylation.
|
|