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Describe the following: (a) Aldol condensation (b) Decarboxylation. |
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Answer» SOLUTION :(a) Aldol condensation : Two molecules of an aldehyde or ketone having `alpha`-H-atoms when TREATED with dil NaOH or `Ba(OH)_(2)` undergo condensation to give `beta`- hydroxyaldehydes or B-hydroxy ketones. This reaction is CALLED aldol condensation. e.g. `underset(underset("(2 molecules)")("ACETALDEHYDE"))(CH_(3)CHO+CH_(3)CHO) OVERSET("Dil. NaOH")to underset("3-Hydroxybutanol (Aldol)")(CH_(3)-underset(H)underset(|)overset(OH)overset(|)C-CH_(2)-CHO)` (b) Decarboxylation : It is the process of removal of a molecule of `CO_(2)` from a carboxylic acid is called decarboxylation. 
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