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Determin the mean and standard deviation for the following distribution |
Answer» ![]() `therefore" Mean " barx=(Sigmaf_(i)x_(i))/(Sigmaf_(i))=(239)/(40)=5.975 ~~6` and`sigma=sqrt((Sigmaf_(i)d_(i)^(2))/(Sigmaf_(i))-((Sigmaf_(i)d_(i))/(Sigmaf_(i)))^(2))=sqrt((325)/(40)-((-1)/(40))^(2))` `=sqrt(8.125-0.000625)=sqrt(8.124375)=2.85` |
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