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Determine block shear strength of tension member shown in figure if grade of steel is Fe410.(a) 309.06 kN(b) 216.49 kN(c) 258.49 kN(d) 326.54 kNThe question was posed to me during an online interview.I need to ask this question from Design of Tension Members in portion Design of Tension Members of Design of Steel Structures

Answer»

The correct answer is (b) 216.49 kN

Easiest explanation: fu = 410 MPA, fy = 250 MPa, γm0 = 1.1, γm1 = 1.25

Avg = ( 1×100 + 50 ) x 8 = 1200 mm^2

Avn = (1×100 + 50 – (2 – 1/2)x20 ) x 8 = 1440 mm^2

Atg = 35 x 8 = 280 mm^2

Atn = (35 – 1/2 x 20) x 8 = 200 mm^2

Tdb1 = (Avgfy/√3 γm0)+(0.9Atnfu/γm1) = [(1200×250/ 1.1x√3) + (0.9x200x410 / 1.25) ] x 10-3 = 216.49 kN

Tdb2 = (Atgfy/ γm0)+(0.9Avnfu/√3 γm1) = [ (0.9x1440x410 / 1.25x√3) + (280×250/1.1) ] x 10-3 = 309.06 kN

Block shear strength of tension MEMBER is 216.49 kN.


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