1.

Determine the age of an ancient wooden piece, if it is known that specific activity of C^(14) nuclide in it amounts to 3/5 of that in freshly fallen trees. The half life of C^(14) nuclide is 5570 yrs

Answer»

`2.2 xx 10^(2) yrs`
`90 xx 10^(1) yrs`
`2.9 xx 10^(4) yrs`
`4.1 xx 10^(3) yrs`

Solution :`N=N_(0) e^(-lambda t), lambda N=3/5 lambda N_(0) or N=3/5 N_(0)`
`3/5 N_(0)=N_(0) e^(-lambda t) or t=(ln ""5/3)/(lambda)`
`RARR t=(ln ""5/3)/((ln 2)/(T))=5570 (ln""5/3)/(ln 2)=4.1 xx 10^(3) yrs`


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