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Determine the charge that produces an electric field strength of 40 V/cm at a distance of 30cm in vacuum(in 10^-8C)(a) 4(b) 2(c) 8(d) 6This question was addressed to me in a national level competition.The question is from Electric Field Intensity in chapter Electrostatic Fields of Electromagnetic Theory

Answer»

The correct CHOICE is (a) 4

Explanation: E = Q/ (4∏εor^2)

Q = (4000 X 0.3^2)/ (9 X 10^9) = 4 X 10^-8 C.



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