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Determine the current through the galvanometer in the circuit. Given :P=2 Omega, Q = 4 Omega, R =8 Omega S =4 Omega G =10 Omega, E =5 and r =0. |
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Answer» Solution :By applying Kirchhoff.s Voltage law we get following EQUATIONS: `2I _(1) + 10 I _(g) - 8I _(2) =0` `4I_(1) - 18 I _(g) - 4 I _(2) =0` `12I _(1) + 10 I _(g) - 8 I _(2) =0` By solving the above equations `I _(g) = 0.12 A` |
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