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Determine the decrease in the weight of a body when it is taken 32 km below the earth surface. Take radius of the earth as 6400 km.A. `1%`B. `2%`C. `1.5%`D. `5%` |
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Answer» Correct Answer - A In this case, `h lt lt R " " therefore g_(h)=g(1-(2h)/(R ))=g-(2gh)/(R )` `therefore g-g_(h)=(2gh)/(R )" "` ……..(1) `therefore` Percentage decrease in weight `= (mg-mg_(h))/(mg)xx100` `=((g-g_(h))/(g))xx100=(2gh)/(gR)xx100 " "` ......from (1) `=(2h)/(R )xx100=(2xx32)/(6400)xx100=1%` `therefore` Percentage decrease = 1% |
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