1.

Determine the density of CsCI which crystallizes in a bcc type structure with an edge length 412.1 pm.

Answer»

SOLUTION :`"Molar mass of cscl"="168.5 g/MOL"`
Number atoms present in PER unit cel for bcc (cscl)
`N=1`
`"Edge length (a) = 412.1 pm"`
`"Density "(rho)=?`
`rho=(nM)/(a^(2)N_(A))`
`=(1xx168.5" g mol"^(-1))/((412.1xx10^(-10)cm)^(3)xx(6.023xx10^(23)"mol"^(-1))`
`=(168.5gcm^(-3))/(6.998xx10^(-23)xx6.023xx10^(23))`
`=(168.5)/(42.148)gcm^(-3)`
`rho=3.997gcm^(-3)`


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