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Determine the electrostatic potential energy of a system consisting of two charges 7 muC and - 2 muC(and with no external field) placed at (-9 cm, 0, 0) and (9 cm, 0, 0) respectively. |
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Answer» Solution :The ELECTROSTATIC potential energy of TWO CHARGES `q_(1) q_(2)` at distance r, WHERER=(9,0,0) - (-9,0,0)CM r=18 cm = 0.18 m `U= (kq_(1)q_(2))/(r)` `= (9xx10^(9)xx7xx10^(-6)xx(-2)xx10^(-6))/(0.18)` `:. U = -0.7 J` |
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