1.

Determine the equilibrium constant of the following reaction at 298 K : 2Fe^(3+)+Sn^(2+) rarr 2Fe^(2+) +Sn^(4+) ("Given: "E_(Sn^(4+)//Sn^(2+))^(@)=0.15" volt, "E_(Fe^(3+)//Fe^(2+))^(@)=0.771" volt" )

Answer»


Solution :CALCULATE `E_(CELL)^(@)`. The value is 0.21 VOLT.
Apply `E_(cell)^(@)=0.0591/2 LOG K`


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