InterviewSolution
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InterviewSolution
| 1. |
Determine the minimum number of dice when we throw all of them we have at least a 50% chance of getting 6. |
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Answer» P(1 time6)+P(2 time 6)...+P(n times 6)`>=1/2` `1-P(no6)>=1/2` `1-(1-1/6)^n>=1/2` `1-1/2>=(5/6)^n` `1/2>=(5/6)^n` `1/2=(5/6)^n` `-log2=n(log5-log6)` `-3.0=n(log10-log2-log2-log3)` `30=n(1-0.3-0.3-0.479)` `n=3.79` `n>=3.79` `n=4` |
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