Determine the number nearest to 110000 but greater than 100000 which i

1.	Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.
Answer» To find: The number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21 Solution: To be exactly divisible by each of 8, 15 and 21,the required number must be divisible by the LCM of 8, 15 and 21 i.e.by 840. Now on dividing 110000 by 840 we get 800 as remainder. Therefore the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21 is 110000 – Remainder ⇒ 110000 – 800 = 109200 Now 109200 gives remainder 0 when divided by 8, 15 and 21 as it is completely divisible by their LCM.

Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.

Answer»

To find:

The number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21

Solution:

To be exactly divisible by each of 8, 15 and 21,the required number must be divisible by the LCM of 8, 15 and 21 i.e.by 840.

Now on dividing 110000 by 840 we get 800 as remainder.

Therefore the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21 is 110000 – Remainder ⇒ 110000 – 800 = 109200

Now 109200 gives remainder 0 when divided by 8, 15 and 21 as it is completely divisible by their LCM.

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