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Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K_(2)SO_(4) in 2 litre of water at 25^(@)C, assuming that it is completely dissociated. |
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Answer» Solution :`K_(2)SO_(4)to2K^(+)+SO_(4)^(-2)` Total number of ions produced = 3 Thereforem i = 3 Given, w = 25 mg = 0.025 g V = 2 L `T=250^(@)C=(25+273)K` = 298 K Also, we know that : `R=0.0821" L atm K"^(-1)mol^(-1)` `M=(2xx39)+(1xx32)+(4xx16)` `= 174 mol^(-1)` Appling the following relation, `pi=i(n)/(V)RT` `= i(w)/(M)(1)/(v)RT` `=(0.025)/(174)XX(1)/(2)xx0.0821xx298` `=5.27xx10^(-3)` atm. |
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