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Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K_2SO_4in 2 litre of water at 25^@C , assuming that it is completely dissociated. |
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Answer» SOLUTION :` K_2SO_4` dissolved = 25 mg = 0.025 g Molar mass of `K_2SO_4 = 2 xx 39 + 32 + 4xx16 = 78 + 32 + 64 = 174 g "mol"^(-1)` As `K_2SO_4` dissociates completely as `K_2SO_4 to2K^(+) + SO_4^(2-)` i.e., ions produced = 3 ` therefore i=3` Applying the following equation `pi = iCRT = i n/V RT=i xx w/W xx 1/V RT` Substituting the values, we get `pi = 3 xx (0.025 g)/(174 g "mol"^(-1)) xx (1)/(2L)xx 0.0821 L atm K^(-1) "mol"^(-1) xx 298 K` `= 5.27 xx 10^(-3) atm` |
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