Determine the percent of increase or decrease. 1. Php 100.00 to Php 300.002. 150kgs to 145 kgs3. 40kms to 72kms4.36 m to 26 ms. inches to 15 indhofULLDOCUBE6. 1.5 liters to 2 litersSolve the following7. Maria was given Php 156.00 discount on a pair of shoesmarked Php 1,200.00. How much was the discount rate andthe selling price?8. Andrea,s pulse rate changed from 70 to 90 afterexercising. What is the percent of increase?9. Paul bought a toy worth Php 180.00 without VAT. If hepaid 12% VAT. How much did he pay in all?10. Lina earned a 10-peso interest in 3 months on her1,000-peso savings. What was the rate of interest peryear?

Determine the percent of increase or decrease. 1. Php 100.00 to Php

1.	Determine the percent of increase or decrease. 1. Php 100.00 to Php 300.002. 150kgs to 145 kgs3. 40kms to 72kms4.36 m to 26 ms. inches to 15 indhofULLDOCUBE6. 1.5 liters to 2 litersSolve the following7. Maria was given Php 156.00 discount on a pair of shoesmarked Php 1,200.00. How much was the discount rate andthe selling price?8. Andrea,s pulse rate changed from 70 to 90 afterexercising. What is the percent of increase?9. Paul bought a toy worth Php 180.00 without VAT. If hepaid 12% VAT. How much did he pay in all?10. Lina earned a 10-peso interest in 3 months on her1,000-peso savings. What was the rate of interest peryear?
Answer» plz MAKE brainlistStep-by-step explanation:Answer:(512)^{-\frac{2}{9}}=\frac{1}{4}(512)−92=41Step-by-step explanation:GIVEN : Expression (512)^{-\frac{2}{9}To find : The value of the expression ?SOLUTION :First we factor 512 so that we get to CONVERT it into the power,512=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2512=2×2×2×2×2×2×2×2×2512=2^9512=29Substitute in expression,(512)^{-\frac{2}{9}}=(2^9)^{-\frac{2}{9}}(512)−92=(29)−92(512)^{-\frac{2}{9}}=(2)^{-\frac{2\times 9}{9}}(512)−92=(2)−92×9(512)^{-\frac{2}{9}}=(2)^{-2}(512)−92=(2)−2(512)^{-\frac{2}{9}}=\frac{1}{2^2}(512)−92=221(512)^{-\frac{2}{9}}=\frac{1}{4}(512)−92=41