1.

Determine the percentage of water of crystallisation, iron , sulphur and oxygen in pure ferrous sulphate (FeSO_(4).7H_(2)O).

Answer»

Solution :The formula mass of of FERROUS SULPHATE
=At. Mass of Fe+At. Mass of S+4X At. Mass of oxygen
+7X Mol. Mass of `H_(2)O`
`=56.0+32.0+4xx16.0+7xx18.0=278.0`
So, % of water of crystallisation `=(126)/(278)xx100=45.32`
% of iron `=(56)/(278)xx100=20.14`
% of SULPHUR=`(32)/(278)xx100=11.51`
% of oxygen`=(64)/(278)xx100=23.02`


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