1.

Determine the potential of the following cell: Pt|H_(2)(g,0.1bar)|H^(+)(aq,10^(-3)M)|| MnO_(4)^(-)(aq,0.1M),Mn^(2+)(aq,0.01M),H^(+)(aq.0.01M)|Pt Given :E_(MnO_(4)^(-)|Mn^(2+))^(0)=1.51V

Answer»

`1.54V`
`1.48V`
`1.84V`
`1.51`

SOLUTION :Anode `H_(2(g))rarr2H^(+)(AQ)+2e^(-)`
(i)Cathode `MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O`
(ii)
`(i)XX(5)`
`(ii)xx(2)`
`E=E^(o)-(0.06)/(10)log,([Mn^(2+)]^(2)[H^(+)]_(a)^(10))/([MnO_(4)^(-)][H^(+)]_(ca)^(16)P_(H2)^(5))`
`=1.51-(0.06)/(10)log,((10^(-2))^(2)xx(10^(-3))^(10))/((10^(-1))^(2)xx(10^(-2))^(16)(10^(-1))^(5))`
`=1.51-(0.06)/(10)log10^(5)`
`=1.51-0.03=1.48V`


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