1.

Determine the self-inductance of a coil, which has a magnetic flux of 50 milliwebers that is produced when a current of 5 A flows through it?(a) 1 × 10^-2 Wb(b) 1 × 10^-3 Wb(c) 100 Wb(d) 1 × 10^3 WbThe question was posed to me in an internship interview.Enquiry is from Electromagnetic Inductance in division Electromagnetic Induction of Physics – Class 12

Answer»

Right choice is (a) 1 × 10^-2 WB

The EXPLANATION is: Self-inductance = \(\frac {Magnetic \, flux}{Current}\)

Self-inductance = \(\frac {50 \times 10^{-3}}{5}\)

Self-inductance = 1 × 10^-2 Wb



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