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develop systems of equations by the substitution method x+3y+2=1 :5x+3y+5= -3 3x+2y+4=2 . 2x+4y+2=5 3x+3y+5=7 3x+2y+4=2 |
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Answer» Answer:1) 3x + 2Y = 11...…(I)2x + 3Y = 4...….(II)from equation 1 y = (11 - 3x)/2substituting in 22x + 3(11 - 3x)/2 = 44x + 33 - 9x = 8-5x = -25x = 5and y = (-2)2) 7x - 2y = 1...…(I)3x + 4y = 15...…(II)from equation 1x = (1 + 2y)/7substituting in 23(1+2y)/7 +4y = 153 + 6y + 28y = 10534y = 102y = 3x = 1Thank You!!Mark as brainliest!! |
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