1.

Dielectric constnat of air is 1.005 and velocity of electromagnetic wave propagating in air is a xx 10^(10)cm//s then a = …….

Answer»

3
`3.55`
`2.5`
`2.8`

Solution :As dielectric constant is 1.005 is considered as 1. So AIR MEDIUM behaves as vacuum and velocity of ELECTROMAGNETIC waves in vacuum is `3xx10^(8)m//s`. So comparing GIVEN SPEED `a xx 10^(8) m//s` with `3xx10^(8)m//s` we have a = 3.


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