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Dielectric strength of air is 3xx10^(6) V.m^(-1). Suppose the radius of a hollow sphere in the Van de Graff generation is R =0.5 m , calculate themaximum potential difference created by this Van de Graaff generator . |
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Answer» Solution :The electric field on the SURFACE of the sphere (by Gauss LAW ) is GIVEN by `E=(1)/(4piepsilon_(0))(Q)/(R^(2))` The potential on the surface of the hollow METALLIC sphere is given by `V=(1)/(4piepsilon_(0))(Q)/( R)=ER` with `V_("max")=E_("max")R` Here `E_("max")=3xx10^(6)(V)/(m)`. So the maximum potential difference created is given by `V_("max")=3xx10^(6)xx0.5=1.5xx10^(6)V` (or) 1.5 million VOLT |
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