Differentiation of log base 7 log x

1.	Differentiation of log base 7 log x
Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>y = log7logx y = logelogxloge7 dydx = 1loge7 (1logx) ddxlog <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> dydx = 1loge7 1log x. <a href="https://interviewquestions.tuteehub.com/tag/1x-283409" style="font-weight:bold;" target="_blank" title="Click to know more about 1X">1X</a> dydx = 1loge7x <a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a> x dydx = 1loge7x log x </p></body></html>

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