Differentiation of log base 7 log x – InterviewSolution

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Differentiation of log base 7 log x

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y = log7logx y = logelogxloge7 dydx = 1loge7 (1logx) ddxlog X dydx = 1loge7 1log x. 1X dydx = 1loge7x LOG x dydx = 1loge7x log x

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