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Differentiation of y= logₐ(x) + logₐ(a) + logₓ(a) |
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Answer» Answer: 1/x ln(a)Step-by-step explanation: y= logₐ(x) + logₐ(a) + logₓ(a) dy/dx = 1/x ln (a) + 0 + 0 =>dy/dx=1/x ln(a) HOPE IT HELPS, PLEASE THANK, FOLLOW AND MARK AS BRAINLIEST. |
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