1.

Dimensional formula of magnetic flux is .......

Answer»

`M^1 L^2 T^(-2) A^(-1)`
`M^1 L^0 T^(-2) A^(-2)`
`M^0 L^(-2) T^(-2) A^3`
`M^1 L^2 T^(-2) A^3`

Solution :`PHI=AB` and `B=F/(IL)`
`therefore [phi]=[A][B]=[A][F/(Il)]`
`=[L^2]xx(M^1L^1T^(-2))/(A^1L^1)`
`=M^1 L^2 T^(-2) A^(-1)`


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