1.

Dimensions of 1 // (mu_(0) epsilon_(0)) is:

Answer»

`L^(2) // T^(2)`
`T^(2) // L^(2)`
`T // L`
`L // T`

Solution :`c=(1)/(SQRT(mu_(0)epsilon_(0)))`
`:. c^(2)=(1)/(mu_(0) epsilon_(0))`
or `L^(2)T^(-2)=(1)/(mu_(0) epsilon_(0))`


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