Dinitrogen and dihydrogen react with each other to produce ammonia according to the chemical equation : ""N_(2)(g)+3H_(2)(g) rarr 2NH_(3)(g) (i) Calculate the mass of ammonia produced if 2.00xx10^(3) g dinitrogen reactw with 1.00xx10^(3)g dihydrogen (ii) Will any of the two reactants remain unreacted? (iii) If yes, which one and what would be its mass?

Dinitrogen and dihydrogen react with each other to produce ammonia acc

1.	Dinitrogen and dihydrogen react with each other to produce ammonia according to the chemical equation : ""N_(2)(g)+3H_(2)(g) rarr 2NH_(3)(g) (i) Calculate the mass of ammonia produced if 2.00xx10^(3) g dinitrogen reactw with 1.00xx10^(3)g dihydrogen (ii) Will any of the two reactants remain unreacted? (iii) If yes, which one and what would be its mass?
Answer» Solution :(i) `"1 mole of N"_(2)," i.e., 28 g react with 3 moles of H"_(2)," i.e., 6 g of H"_(2)` `therefore " 2000g of N"_(2)" will react with "H_(2)=(6)/(28)xx200g=428.6g." Thus, "N_(2)" is the limiting reagent while H"_(2) " isthe excess reagent."` 2 moles of `N_(2)`, i.e., 28 g of `N_(2)` produce `NH_(3)` = 2 moles = 34 g `therefore "2000 g of N"_(2)" will produce NH"_(3)=(34)/(28)xx2000g=22428.57g` (ii) `H_(2)` will remain unreacted. (iii) MASS LEFT unreacted `=1000g-428.6g=571.4g`