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Direction : The questions 57, 58 and 59 are based on following paragraph : Radiation emitted when an electron jumps from n = 3 to n=1 orbit in H_(2) atom, fall on a metal to produce photoelectrons. Electrons fall on the metal surface with maximum K.E. in a direction perpendicular to a magnetic field of 1/320 T in a radius of 10m^(-3). The K.E. of the electrons is |
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Answer» `2xx10^(-19)J` `[-(1.51)+3.4]eV=1.89eV` |
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