Direction : The questions 57, 58 and 59 are based on following paragraph : Radiation emitted when an electron jumps from n = 3 to n=1 orbit in H_(2) atom, fall on a metal to produce photoelectrons. Electrons fall on the metal surface with maximum K.E. in a direction perpendicular to a magnetic field of 1/320 T in a radius of 10m^(-3). Wavelength of radiation is

Direction : The questions 57, 58 and 59 are based on following paragra

1.	Direction : The questions 57, 58 and 59 are based on following paragraph : Radiation emitted when an electron jumps from n = 3 to n=1 orbit in H_(2) atom, fall on a metal to produce photoelectrons. Electrons fall on the metal surface with maximum K.E. in a direction perpendicular to a magnetic field of 1/320 T in a radius of 10m^(-3). Wavelength of radiation is
Answer» 5200 A 6563 A 4500 A 7000 A Solution :`c=V lambda rArr lambda=(c)/(v)=(HC)/(HV)=6567Å`

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